Base | Representation |
---|---|
bin | 101101101110101110011011… |
… | …010111010001111100111001 |
3 | 222101010011201110210021010220 |
4 | 231232232123113101330321 |
5 | 202330144441234003423 |
6 | 1551430352113130253 |
7 | 60235442266105236 |
oct | 5556563327217471 |
9 | 871104643707126 |
10 | 201123040141113 |
11 | 590a1890990382 |
12 | 1a682bab259989 |
13 | 882ba8a53c13c |
14 | 379459b06878d |
15 | 183ba1262d9e3 |
hex | b6eb9b5d1f39 |
201123040141113 has 16 divisors (see below), whose sum is σ = 268186573025856. Its totient is φ = 134070767550720.
The previous prime is 201123040141103. The next prime is 201123040141147. The reversal of 201123040141113 is 311141040321102.
It is not a de Polignac number, because 201123040141113 - 217 = 201123040010041 is a prime.
It is a super-2 number, since 2×2011230401411132 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (201123040141103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3163424181 + ... + 3163487757.
It is an arithmetic number, because the mean of its divisors is an integer number (16761660814116).
Almost surely, 2201123040141113 is an apocalyptic number.
It is an amenable number.
201123040141113 is a deficient number, since it is larger than the sum of its proper divisors (67063532884743).
201123040141113 is a wasteful number, since it uses less digits than its factorization.
201123040141113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135544.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 201123040141113 its reverse (311141040321102), we get a palindrome (512264080462215).
The spelling of 201123040141113 in words is "two hundred one trillion, one hundred twenty-three billion, forty million, one hundred forty-one thousand, one hundred thirteen".
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