201130111320133 has 4 divisors (see below), whose sum is σ = 201154381886080. Its totient is φ = 201105840754188.

The previous prime is 201130111320107. The next prime is 201130111320139. The reversal of 201130111320133 is 331023111031102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201130111320133 - 2⁴⁵ = 165945739231301 is a prime.

It is a super-2 number, since 2×201130111320133² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201130111320139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12135270543 + ... + 12135287116.

It is an arithmetic number, because the mean of its divisors is an integer number (50288595471520).

Almost surely, 2^{201130111320133} is an apocalyptic number.

It is an amenable number.

201130111320133 is a deficient number, since it is larger than the sum of its proper divisors (24270565947).

201130111320133 is an equidigital number, since it uses as much as digits as its factorization.

201130111320133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24270565946.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 201130111320133 its reverse (331023111031102), we get a palindrome (532153222351235).

The spelling of 201130111320133 in words is "two hundred one trillion, one hundred thirty billion, one hundred eleven million, three hundred twenty thousand, one hundred thirty-three".