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20113100131103 = 72410471431247
BaseRepresentation
bin1001001001010111100100…
…01100000100101100011111
32122012210102112022110102022
410210223302030010230133
510114013112113143403
6110435455230250355
74144060241204300
oct444536214045437
978183375273368
1020113100131103
116454a10749571
12230a0786569bb
13b2b870b53535
144d769d0707a7
1524d2c4200d38
hex124af2304b1f

20113100131103 has 6 divisors (see below), whose sum is σ = 23396871581136. Its totient is φ = 17239800112332.

The previous prime is 20113100131087. The next prime is 20113100131123. The reversal of 20113100131103 is 30113100131102.

It is not a de Polignac number, because 20113100131103 - 24 = 20113100131087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20113100131123) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 205235715575 + ... + 205235715672.

It is an arithmetic number, because the mean of its divisors is an integer number (3899478596856).

Almost surely, 220113100131103 is an apocalyptic number.

20113100131103 is a deficient number, since it is larger than the sum of its proper divisors (3283771450033).

20113100131103 is an equidigital number, since it uses as much as digits as its factorization.

20113100131103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 410471431261 (or 410471431254 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 20113100131103 its reverse (30113100131102), we get a palindrome (50226200262205).

Subtracting 20113100131103 from its reverse (30113100131102), we obtain a palindrome (9999999999999).

The spelling of 20113100131103 in words is "twenty trillion, one hundred thirteen billion, one hundred million, one hundred thirty-one thousand, one hundred three".

Divisors: 1 7 49 410471431247 2873300018729 20113100131103