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2011312132133 = 2387448353571
BaseRepresentation
bin11101010001001011100…
…010111001000000100101
321010021112210121200222212
4131101023202321000211
5230423131401212013
64135552315133205
7265212122020103
oct35211342710045
97107483550885
102011312132133
11705aa129a117
12285980444205
13117887046995
146d4c2db0c73
15374bb1756a8
hex1d44b8b9025

2011312132133 has 4 divisors (see below), whose sum is σ = 2098760485728. Its totient is φ = 1923863778540.

The previous prime is 2011312132129. The next prime is 2011312132139. The reversal of 2011312132133 is 3312312131102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2011312132133 - 22 = 2011312132129 is a prime.

It is a super-2 number, since 2×20113121321332 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 87448353571 = 2011312132133 / (2 + 0 + 1 + 1 + 3 + 1 + 2 + 1 + 3 + 2 + 1 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2011312132099 and 2011312132108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2011312132139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43724176763 + ... + 43724176808.

It is an arithmetic number, because the mean of its divisors is an integer number (524690121432).

Almost surely, 22011312132133 is an apocalyptic number.

2011312132133 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2011312132133 is a deficient number, since it is larger than the sum of its proper divisors (87448353595).

2011312132133 is an equidigital number, since it uses as much as digits as its factorization.

2011312132133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87448353594.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 2011312132133 its reverse (3312312131102), we get a palindrome (5323624263235).

The spelling of 2011312132133 in words is "two trillion, eleven billion, three hundred twelve million, one hundred thirty-two thousand, one hundred thirty-three".

Divisors: 1 23 87448353571 2011312132133