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2011331240131 = 3122096442259
BaseRepresentation
bin11101010001001100101…
…011110010000011000011
321010021121010120111020111
4131101030223302003003
5230423201244141011
64135554240452151
7265212443312413
oct35211453620303
97107533514214
102011331240131
11706001060254
1228598691a057
1311788aca70a5
146d4c5746643
15374bcb9c121
hex1d44caf20c3

2011331240131 has 4 divisors (see below), whose sum is σ = 2011337994600. Its totient is φ = 2011324485664.

The previous prime is 2011331240129. The next prime is 2011331240167. The reversal of 2011331240131 is 1310421331102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2011331240131 - 21 = 2011331240129 is a prime.

It is a super-2 number, since 2×20113312401312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2011331240431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2908921 + ... + 3533338.

It is an arithmetic number, because the mean of its divisors is an integer number (502834498650).

Almost surely, 22011331240131 is an apocalyptic number.

2011331240131 is a deficient number, since it is larger than the sum of its proper divisors (6754469).

2011331240131 is an equidigital number, since it uses as much as digits as its factorization.

2011331240131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6754468.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 2011331240131 its reverse (1310421331102), we get a palindrome (3321752571233).

The spelling of 2011331240131 in words is "two trillion, eleven billion, three hundred thirty-one million, two hundred forty thousand, one hundred thirty-one".

Divisors: 1 312209 6442259 2011331240131