Base | Representation |
---|---|
bin | 11101010001001100101… |
… | …011110010000011100111 |
3 | 21010021121010120111021211 |
4 | 131101030223302003213 |
5 | 230423201244141132 |
6 | 4135554240452251 |
7 | 265212443312464 |
oct | 35211453620347 |
9 | 7107533514254 |
10 | 2011331240167 |
11 | 706001060287 |
12 | 28598691a087 |
13 | 11788aca7102 |
14 | 6d4c574666b |
15 | 374bcb9c147 |
hex | 1d44caf20e7 |
2011331240167 has 2 divisors, whose sum is σ = 2011331240168. Its totient is φ = 2011331240166.
The previous prime is 2011331240129. The next prime is 2011331240189. The reversal of 2011331240167 is 7610421331102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011331240167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011331240467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005665620083 + 1005665620084.
It is an arithmetic number, because the mean of its divisors is an integer number (1005665620084).
Almost surely, 22011331240167 is an apocalyptic number.
2011331240167 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011331240167 is an equidigital number, since it uses as much as digits as its factorization.
2011331240167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 2011331240167 its reverse (7610421331102), we get a palindrome (9621752571269).
The spelling of 2011331240167 in words is "two trillion, eleven billion, three hundred thirty-one million, two hundred forty thousand, one hundred sixty-seven".
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