Base | Representation |
---|---|
bin | 10010101110110110… |
… | …010011100000010001 |
3 | 1220220201210120002120 |
4 | 102232312103200101 |
5 | 312143003343213 |
6 | 13123454404453 |
7 | 1311266400324 |
oct | 225666234021 |
9 | 56821716076 |
10 | 20113340433 |
11 | 85915023aa |
12 | 3a93b00729 |
13 | 1b8700c594 |
14 | d8b38a7bb |
15 | 7caba8423 |
hex | 4aed93811 |
20113340433 has 4 divisors (see below), whose sum is σ = 26817787248. Its totient is φ = 13408893620.
The previous prime is 20113340353. The next prime is 20113340447. The reversal of 20113340433 is 33404331102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20113340433 - 29 = 20113339921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20113340483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3352223403 + ... + 3352223408.
It is an arithmetic number, because the mean of its divisors is an integer number (6704446812).
Almost surely, 220113340433 is an apocalyptic number.
It is an amenable number.
20113340433 is a deficient number, since it is larger than the sum of its proper divisors (6704446815).
20113340433 is an equidigital number, since it uses as much as digits as its factorization.
20113340433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6704446814.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 20113340433 its reverse (33404331102), we get a palindrome (53517671535).
The spelling of 20113340433 in words is "twenty billion, one hundred thirteen million, three hundred forty thousand, four hundred thirty-three".
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