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20113413 = 36704471
BaseRepresentation
bin100110010111…
…0100000000101
31101211212102020
41030232200011
520122112123
61555033353
7332650455
oct114564005
941755366
1020113413
1110398561
12689b859
134222c38
142957d65
151b747e3
hex132e805

20113413 has 4 divisors (see below), whose sum is σ = 26817888. Its totient is φ = 13408940.

The previous prime is 20113403. The next prime is 20113417. The reversal of 20113413 is 31431102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20113413 - 213 = 20105221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20113392 and 20113401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20113417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3352233 + ... + 3352238.

It is an arithmetic number, because the mean of its divisors is an integer number (6704472).

Almost surely, 220113413 is an apocalyptic number.

It is an amenable number.

20113413 is a deficient number, since it is larger than the sum of its proper divisors (6704475).

20113413 is an equidigital number, since it uses as much as digits as its factorization.

20113413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6704474.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 20113413 is about 4484.7979887616. The cubic root of 20113413 is about 271.9538786058.

Adding to 20113413 its reverse (31431102), we get a palindrome (51544515).

The spelling of 20113413 in words is "twenty million, one hundred thirteen thousand, four hundred thirteen".

Divisors: 1 3 6704471 20113413