Base | Representation |
---|---|
bin | 1011101101010011110… |
… | …1001101101001110001 |
3 | 201020011212212100101102 |
4 | 2323110331031221301 |
5 | 11243414133441423 |
6 | 232223020214145 |
7 | 20350316641400 |
oct | 2732475155161 |
9 | 636155770342 |
10 | 201141312113 |
11 | 78338032955 |
12 | 32b9599a355 |
13 | 15c769059a1 |
14 | 9a418d5637 |
15 | 537376ac28 |
hex | 2ed4f4da71 |
201141312113 has 48 divisors (see below), whose sum is σ = 255920974848. Its totient is φ = 156917376000.
The previous prime is 201141312107. The next prime is 201141312121. The reversal of 201141312113 is 311213141102.
It is a de Polignac number, because none of the positive numbers 2k-201141312113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201141312413) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 63032348 + ... + 63035538.
It is an arithmetic number, because the mean of its divisors is an integer number (5331686976).
Almost surely, 2201141312113 is an apocalyptic number.
It is an amenable number.
201141312113 is a deficient number, since it is larger than the sum of its proper divisors (54779662735).
201141312113 is a wasteful number, since it uses less digits than its factorization.
201141312113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5694 (or 5687 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 201141312113 its reverse (311213141102), we get a palindrome (512354453215).
The spelling of 201141312113 in words is "two hundred one billion, one hundred forty-one million, three hundred twelve thousand, one hundred thirteen".
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