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201142002113 = 1330071514531
BaseRepresentation
bin1011101101010011111…
…1110110000111000001
3201020011221011101212222
42323110333312013001
511243414323031423
6232223043100425
720350325544143
oct2732477660701
9636157141788
10201142002113
11783384642a8
1232b96071715
1315c76ab7a80
149a41a34c93
1553738553c8
hex2ed4ff61c1

201142002113 has 8 divisors (see below), whose sum is σ = 216622088256. Its totient is φ = 185663005200.

The previous prime is 201142002107. The next prime is 201142002133. The reversal of 201142002113 is 311200241102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201142002113 - 214 = 201141985729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201142002091 and 201142002100.

It is not an unprimeable number, because it can be changed into a prime (201142002133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 133658 + ... + 648188.

It is an arithmetic number, because the mean of its divisors is an integer number (27077761032).

Almost surely, 2201142002113 is an apocalyptic number.

It is an amenable number.

201142002113 is a deficient number, since it is larger than the sum of its proper divisors (15480086143).

201142002113 is a wasteful number, since it uses less digits than its factorization.

201142002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 544615.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 201142002113 its reverse (311200241102), we get a palindrome (512342243215).

The spelling of 201142002113 in words is "two hundred one billion, one hundred forty-two million, two thousand, one hundred thirteen".

Divisors: 1 13 30071 390923 514531 6688903 15472461701 201142002113