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2012001001113 = 31471455925901
BaseRepresentation
bin11101010001110100100…
…110101101111010011001
321010100022210211212120210
4131101310212231322121
5230431034224013423
64140144524041333
7265235155221345
oct35216446557231
97110283755523
102012001001113
11706315126624
12285b33093249
1311796698976c
146d54a68c625
153750b899b93
hex1d4749ade99

2012001001113 has 8 divisors (see below), whose sum is σ = 2684491710976. Its totient is φ = 1340422146000.

The previous prime is 2012001001103. The next prime is 2012001001117. The reversal of 2012001001113 is 3111001002102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2012001001113 - 25 = 2012001001081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012001001117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227958538 + ... + 227967363.

It is an arithmetic number, because the mean of its divisors is an integer number (335561463872).

Almost surely, 22012001001113 is an apocalyptic number.

It is an amenable number.

2012001001113 is a deficient number, since it is larger than the sum of its proper divisors (672490709863).

2012001001113 is a wasteful number, since it uses less digits than its factorization.

2012001001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 455927375.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 2012001001113 its reverse (3111001002102), we get a palindrome (5123002003215).

The spelling of 2012001001113 in words is "two trillion, twelve billion, one million, one thousand, one hundred thirteen".

Divisors: 1 3 1471 4413 455925901 1367777703 670667000371 2012001001113