Base | Representation |
---|---|
bin | 11101010001110100100… |
… | …110101101111010011101 |
3 | 21010100022210211212120221 |
4 | 131101310212231322131 |
5 | 230431034224013432 |
6 | 4140144524041341 |
7 | 265235155221352 |
oct | 35216446557235 |
9 | 7110283755527 |
10 | 2012001001117 |
11 | 706315126628 |
12 | 285b33093251 |
13 | 117966989773 |
14 | 6d54a68c629 |
15 | 3750b899b97 |
hex | 1d4749ade9d |
2012001001117 has 2 divisors, whose sum is σ = 2012001001118. Its totient is φ = 2012001001116.
The previous prime is 2012001001103. The next prime is 2012001001121. The reversal of 2012001001117 is 7111001002102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1988680962436 + 23320038681 = 1410206^2 + 152709^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012001001117 - 235 = 1977641262749 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2012001001117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012001001187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006000500558 + 1006000500559.
It is an arithmetic number, because the mean of its divisors is an integer number (1006000500559).
Almost surely, 22012001001117 is an apocalyptic number.
It is an amenable number.
2012001001117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012001001117 is an equidigital number, since it uses as much as digits as its factorization.
2012001001117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 16.
Adding to 2012001001117 its reverse (7111001002102), we get a palindrome (9123002003219).
The spelling of 2012001001117 in words is "two trillion, twelve billion, one million, one thousand, one hundred seventeen".
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