Base | Representation |
---|---|
bin | 11101010001110100101… |
… | …010111111010100110011 |
3 | 21010100022212221202210111 |
4 | 131101310222333110303 |
5 | 230431040020333021 |
6 | 4140145004042151 |
7 | 265235200564351 |
oct | 35216452772463 |
9 | 7110285852714 |
10 | 2012002121011 |
11 | 706315820a63 |
12 | 285b33533357 |
13 | 117966c8c41c |
14 | 6d54a8a07d1 |
15 | 3750ba1b8e1 |
hex | 1d474abf533 |
2012002121011 has 4 divisors (see below), whose sum is σ = 2066380556752. Its totient is φ = 1957623685272.
The previous prime is 2012002120967. The next prime is 2012002121021. The reversal of 2012002121011 is 1101212002102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2012002121011 - 229 = 2011465250099 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2012002120982 and 2012002121000.
It is not an unprimeable number, because it can be changed into a prime (2012002121021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27189217815 + ... + 27189217888.
It is an arithmetic number, because the mean of its divisors is an integer number (516595139188).
Almost surely, 22012002121011 is an apocalyptic number.
2012002121011 is a deficient number, since it is larger than the sum of its proper divisors (54378435741).
2012002121011 is an equidigital number, since it uses as much as digits as its factorization.
2012002121011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54378435740.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2012002121011 its reverse (1101212002102), we get a palindrome (3113214123113).
The spelling of 2012002121011 in words is "two trillion, twelve billion, two million, one hundred twenty-one thousand, eleven".
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