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2012012013023 = 29107648408641
BaseRepresentation
bin11101010001110101010…
…000101110010111011111
321010100100120120100002022
4131101311100232113133
5230431100033404043
64140150000050355
7265235350634135
oct35216520562737
97110316510068
102012012013023
11706320367a81
12285b369039bb
13117969043a9c
146d54bd17755
153750c822868
hex1d47542e5df

2012012013023 has 8 divisors (see below), whose sum is σ = 2100844000080. Its totient is φ = 1924476843520.

The previous prime is 2012012013007. The next prime is 2012012013029. The reversal of 2012012013023 is 3203102102102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2012012013023 - 24 = 2012012013007 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2012012012992 and 2012012013010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2012012013029) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 324201218 + ... + 324207423.

It is an arithmetic number, because the mean of its divisors is an integer number (262605500010).

Almost surely, 22012012013023 is an apocalyptic number.

2012012013023 is a deficient number, since it is larger than the sum of its proper divisors (88831987057).

2012012013023 is a wasteful number, since it uses less digits than its factorization.

2012012013023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 648408777.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2012012013023 its reverse (3203102102102), we get a palindrome (5215114115125).

The spelling of 2012012013023 in words is "two trillion, twelve billion, twelve million, thirteen thousand, twenty-three".

Divisors: 1 29 107 3103 648408641 18803850589 69379724587 2012012013023