Base | Representation |
---|---|
bin | 11101010001110101010… |
… | …001011111001111010001 |
3 | 21010100100120221111200022 |
4 | 131101311101133033101 |
5 | 230431100111310301 |
6 | 4140150004233225 |
7 | 265235352426554 |
oct | 35216521371721 |
9 | 7110316844608 |
10 | 2012012213201 |
11 | 706320494411 |
12 | 285b3699b815 |
13 | 1179690b3c33 |
14 | 6d54bd6a69b |
15 | 3750c861d1b |
hex | 1d47545f3d1 |
2012012213201 has 4 divisors (see below), whose sum is σ = 2012032196532. Its totient is φ = 2011992229872.
The previous prime is 2012012213191. The next prime is 2012012213207. The reversal of 2012012213201 is 1023122102102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1190226450625 + 821785762576 = 1090975^2 + 906524^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012012213201 - 218 = 2012011951057 is a prime.
It is a super-3 number, since 3×20120122132013 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2012012213201.
It is not an unprimeable number, because it can be changed into a prime (2012012213207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9839870 + ... + 10042263.
It is an arithmetic number, because the mean of its divisors is an integer number (503008049133).
Almost surely, 22012012213201 is an apocalyptic number.
It is an amenable number.
2012012213201 is a deficient number, since it is larger than the sum of its proper divisors (19983331).
2012012213201 is a wasteful number, since it uses less digits than its factorization.
2012012213201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19983330.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2012012213201 its reverse (1023122102102), we get a palindrome (3035134315303).
The spelling of 2012012213201 in words is "two trillion, twelve billion, twelve million, two hundred thirteen thousand, two hundred one".
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