Base | Representation |
---|---|
bin | 101101101111110111001111… |
… | …010111011110101110100001 |
3 | 222101101122112002210012211220 |
4 | 231233313033113132232201 |
5 | 202332440100314120001 |
6 | 1551530322042125253 |
7 | 60244210563110220 |
oct | 5557671727365641 |
9 | 871348462705756 |
10 | 201201222020001 |
11 | 59121a60586125 |
12 | 1a69618a1b0829 |
13 | 8836269aaaa38 |
14 | 3798296570cb7 |
15 | 183da8b1b4c36 |
hex | b6fdcf5deba1 |
201201222020001 has 16 divisors (see below), whose sum is σ = 306644471192448. Its totient is φ = 114952577040000.
The previous prime is 201201222019999. The next prime is 201201222020063. The reversal of 201201222020001 is 100020222102102.
It is not a de Polignac number, because 201201222020001 - 21 = 201201222019999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201201223020001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 814449750 + ... + 814696751.
It is an arithmetic number, because the mean of its divisors is an integer number (19165279449528).
Almost surely, 2201201222020001 is an apocalyptic number.
201201222020001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
201201222020001 is a deficient number, since it is larger than the sum of its proper divisors (105443249172447).
201201222020001 is a wasteful number, since it uses less digits than its factorization.
201201222020001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1629152392.
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 201201222020001 its reverse (100020222102102), we get a palindrome (301221444122103).
The spelling of 201201222020001 in words is "two hundred one trillion, two hundred one billion, two hundred twenty-two million, twenty thousand, one".
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