Search a number
-
+
20120202103 = 57601349303
BaseRepresentation
bin10010101111010000…
…011110101101110111
31220221012201011112111
4102233100132231313
5312201232431403
613124301431451
71311411616231
oct225720365567
956835634474
1020120202103
118595369701
123a9626b587
131b88572841
14d8c255251
157cb5b156d
hex4af41eb77

20120202103 has 4 divisors (see below), whose sum is σ = 20120609008. Its totient is φ = 20119795200.

The previous prime is 20120202101. The next prime is 20120202107. The reversal of 20120202103 is 30120202102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20120202103 - 21 = 20120202101 is a prime.

It is a super-3 number, since 3×201202021033 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20120202101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117051 + ... + 232252.

It is an arithmetic number, because the mean of its divisors is an integer number (5030152252).

Almost surely, 220120202103 is an apocalyptic number.

20120202103 is a deficient number, since it is larger than the sum of its proper divisors (406905).

20120202103 is an equidigital number, since it uses as much as digits as its factorization.

20120202103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 406904.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 20120202103 its reverse (30120202102), we get a palindrome (50240404205).

Subtracting 20120202103 from its reverse (30120202102), we obtain a palindrome (9999999999).

The spelling of 20120202103 in words is "twenty billion, one hundred twenty million, two hundred two thousand, one hundred three".

Divisors: 1 57601 349303 20120202103