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20120313003103 = 70128702301003
BaseRepresentation
bin1001001001100101000000…
…00110111111110001011111
32122020111001012121022200201
410210302200012333301133
510114122400112044403
6110443051051204331
74144434053461525
oct444624006776137
978214035538621
1020120313003103
116457a82178005
12230b5501466a7
13b2c45029c631
144d7b84da0315
1524d59756821d
hex124ca01bfc5f

20120313003103 has 4 divisors (see below), whose sum is σ = 20149015304808. Its totient is φ = 20091610701400.

The previous prime is 20120313003071. The next prime is 20120313003127. The reversal of 20120313003103 is 30130031302102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20120313003103 - 25 = 20120313003071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20120313003143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14351149801 + ... + 14351151202.

It is an arithmetic number, because the mean of its divisors is an integer number (5037253826202).

Almost surely, 220120313003103 is an apocalyptic number.

20120313003103 is a deficient number, since it is larger than the sum of its proper divisors (28702301705).

20120313003103 is an equidigital number, since it uses as much as digits as its factorization.

20120313003103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28702301704.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 20120313003103 its reverse (30130031302102), we get a palindrome (50250344305205).

The spelling of 20120313003103 in words is "twenty trillion, one hundred twenty billion, three hundred thirteen million, three thousand, one hundred three".

Divisors: 1 701 28702301003 20120313003103