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201203142143 = 792546875217
BaseRepresentation
bin1011101101100010100…
…1000100110111111111
3201020100012012122020112
42323120221010313333
511244031001022033
6232233105340235
720352000330023
oct2733051046777
9636305178215
10201203142143
1178369a23753
1232bb263767b
1315c866738c3
149a49bcc383
155378dd0c48
hex2ed8a44dff

201203142143 has 4 divisors (see below), whose sum is σ = 203750017440. Its totient is φ = 198656266848.

The previous prime is 201203142059. The next prime is 201203142181. The reversal of 201203142143 is 341241302102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201203142143 - 214 = 201203125759 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201203147143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1273437530 + ... + 1273437687.

It is an arithmetic number, because the mean of its divisors is an integer number (50937504360).

Almost surely, 2201203142143 is an apocalyptic number.

201203142143 is a deficient number, since it is larger than the sum of its proper divisors (2546875297).

201203142143 is an equidigital number, since it uses as much as digits as its factorization.

201203142143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2546875296.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 201203142143 its reverse (341241302102), we get a palindrome (542444444245).

The spelling of 201203142143 in words is "two hundred one billion, two hundred three million, one hundred forty-two thousand, one hundred forty-three".

Divisors: 1 79 2546875217 201203142143