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201211000000201 = 599335911519199
BaseRepresentation
bin101101110000000000010110…
…001011100000111011001001
3222101102120202112210002001201
4231300000112023200323021
5202333120112000001301
61551535020214144201
760245005103424142
oct5560002613407311
9871376675702051
10201211000000201
1159126118a383a4
121a698058952061
1388371677a1339
14379894301cac9
15183de5e819201
hexb700162e0ec9

201211000000201 has 4 divisors (see below), whose sum is σ = 201546911520000. Its totient is φ = 200875088480404.

The previous prime is 201211000000193. The next prime is 201211000000261. The reversal of 201211000000201 is 102000000112102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201211000000201 - 23 = 201211000000193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201211000000261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167955759001 + ... + 167955760198.

It is an arithmetic number, because the mean of its divisors is an integer number (50386727880000).

Almost surely, 2201211000000201 is an apocalyptic number.

It is an amenable number.

201211000000201 is a deficient number, since it is larger than the sum of its proper divisors (335911519799).

201211000000201 is an equidigital number, since it uses as much as digits as its factorization.

201211000000201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 335911519798.

The product of its (nonzero) digits is 8, while the sum is 10.

Adding to 201211000000201 its reverse (102000000112102), we get a palindrome (303211000112303).

The spelling of 201211000000201 in words is "two hundred one trillion, two hundred eleven billion, two hundred one", and thus it is an aban number.

Divisors: 1 599 335911519199 201211000000201