Base | Representation |
---|---|
bin | 1001001001100110100010… |
… | …11001111001000110100111 |
3 | 2122020120011211211011011201 |
4 | 10210303101121321012213 |
5 | 10114131043322240403 |
6 | 110443305113343331 |
7 | 4144463415253234 |
oct | 444632131710647 |
9 | 78216154734151 |
10 | 20121140040103 |
11 | 6458366aa5163 |
12 | 230b741107b47 |
13 | b2c55272a93b |
14 | 4d7c22b6678b |
15 | 24d5e4e8121d |
hex | 124cd16791a7 |
20121140040103 has 4 divisors (see below), whose sum is σ = 20404536378768. Its totient is φ = 19837743701440.
The previous prime is 20121140040061. The next prime is 20121140040107. The reversal of 20121140040103 is 30104004112102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20121140040103 - 237 = 19983701086631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20121140040107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141698169226 + ... + 141698169367.
It is an arithmetic number, because the mean of its divisors is an integer number (5101134094692).
Almost surely, 220121140040103 is an apocalyptic number.
20121140040103 is a deficient number, since it is larger than the sum of its proper divisors (283396338665).
20121140040103 is an equidigital number, since it uses as much as digits as its factorization.
20121140040103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283396338664.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 20121140040103 its reverse (30104004112102), we get a palindrome (50225144152205).
The spelling of 20121140040103 in words is "twenty trillion, one hundred twenty-one billion, one hundred forty million, forty thousand, one hundred three".
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