201212013000041 has 4 divisors (see below), whose sum is σ = 201214113408084. Its totient is φ = 201209912592000.

The previous prime is 201212013000023. The next prime is 201212013000077. The reversal of 201212013000041 is 140000310212102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 138896713848025 + 62315299152016 = 11785445^2 + 7894004^2 .

It is a cyclic number.

It is not a de Polignac number, because 201212013000041 - 2¹⁰ = 201212012999017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201212012999983 and 201212013000019.

It is not an unprimeable number, because it can be changed into a prime (201212013000001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1050060320 + ... + 1050251921.

It is an arithmetic number, because the mean of its divisors is an integer number (50303528352021).

Almost surely, 2^{201212013000041} is an apocalyptic number.

It is an amenable number.

201212013000041 is a deficient number, since it is larger than the sum of its proper divisors (2100408043).

201212013000041 is an equidigital number, since it uses as much as digits as its factorization.

201212013000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2100408042.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 201212013000041 its reverse (140000310212102), we get a palindrome (341212323212143).

The spelling of 201212013000041 in words is "two hundred one trillion, two hundred twelve billion, thirteen million, forty-one", and thus it is an aban number.