Base | Representation |
---|---|
bin | 10010101111010100… |
… | …010101010011000111 |
3 | 1220221021121110222220 |
4 | 102233110111103013 |
5 | 312202012241403 |
6 | 13124335223423 |
7 | 1311423323646 |
oct | 225724252307 |
9 | 56837543886 |
10 | 20121212103 |
11 | 8595999513 |
12 | 3a96677b73 |
13 | 1b88837485 |
14 | d8c43935d |
15 | 7cb710953 |
hex | 4af5154c7 |
20121212103 has 4 divisors (see below), whose sum is σ = 26828282808. Its totient is φ = 13414141400.
The previous prime is 20121212099. The next prime is 20121212117. The reversal of 20121212103 is 30121212102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20121212103 - 22 = 20121212099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20121212183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3353535348 + ... + 3353535353.
It is an arithmetic number, because the mean of its divisors is an integer number (6707070702).
Almost surely, 220121212103 is an apocalyptic number.
20121212103 is a deficient number, since it is larger than the sum of its proper divisors (6707070705).
20121212103 is an equidigital number, since it uses as much as digits as its factorization.
20121212103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6707070704.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 20121212103 its reverse (30121212102), we get a palindrome (50242424205).
Subtracting 20121212103 from its reverse (30121212102), we obtain a palindrome (9999999999).
The spelling of 20121212103 in words is "twenty billion, one hundred twenty-one million, two hundred twelve thousand, one hundred three".
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