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201212201101 = 414907614661
BaseRepresentation
bin1011101101100100101…
…1101000100010001101
3201020100211020212210111
42323121023220202031
511244040310413401
6232234031440021
720352140330002
oct2733113504215
9636324225714
10201212201101
117837405089a
1232bb5686011
1315c884c6032
149a4b0a98a9
155379abee51
hex2ed92e888d

201212201101 has 4 divisors (see below), whose sum is σ = 206119815804. Its totient is φ = 196304586400.

The previous prime is 201212201023. The next prime is 201212201149. The reversal of 201212201101 is 101102212102.

201212201101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 58232929225 + 142979271876 = 241315^2 + 378126^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201212201101 is a prime.

It is a super-2 number, since 2×2012122011012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201212261101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2453807290 + ... + 2453807371.

It is an arithmetic number, because the mean of its divisors is an integer number (51529953951).

Almost surely, 2201212201101 is an apocalyptic number.

It is an amenable number.

201212201101 is a deficient number, since it is larger than the sum of its proper divisors (4907614703).

201212201101 is an equidigital number, since it uses as much as digits as its factorization.

201212201101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4907614702.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 201212201101 its reverse (101102212102), we get a palindrome (302314413203).

It can be divided in two parts, 20121 and 2201101, that added together give a palindrome (2221222).

The spelling of 201212201101 in words is "two hundred one billion, two hundred twelve million, two hundred one thousand, one hundred one".

Divisors: 1 41 4907614661 201212201101