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2012122202001 = 3670707400667
BaseRepresentation
bin11101010001111011110…
…101000011111110010001
321010100122020220111221120
4131101323311003332101
5230431311240431001
64140204533512453
7265241156343612
oct35217365037621
97110566814846
102012122202001
1170637758864a
12285b677a2729
13117985b14172
146d55c7dbc09
153751733b236
hex1d47bd43f91

2012122202001 has 4 divisors (see below), whose sum is σ = 2682829602672. Its totient is φ = 1341414801332.

The previous prime is 2012122201987. The next prime is 2012122202081. The reversal of 2012122202001 is 1002022212102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2012122202001 - 29 = 2012122201489 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2012122202081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335353700331 + ... + 335353700336.

It is an arithmetic number, because the mean of its divisors is an integer number (670707400668).

Almost surely, 22012122202001 is an apocalyptic number.

It is an amenable number.

2012122202001 is a deficient number, since it is larger than the sum of its proper divisors (670707400671).

2012122202001 is an equidigital number, since it uses as much as digits as its factorization.

2012122202001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670707400670.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 2012122202001 its reverse (1002022212102), we get a palindrome (3014144414103).

The spelling of 2012122202001 in words is "two trillion, twelve billion, one hundred twenty-two million, two hundred two thousand, one".

Divisors: 1 3 670707400667 2012122202001