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20121302013 = 36707100671
BaseRepresentation
bin10010101111010100…
…101011001111111101
31220221021210001022220
4102233110223033331
5312202023131023
613124341155553
71311424150041
oct225724531775
956837701286
1020121302013
118595a5001a
123a966bbbb9
131b88869387
14d8c460021
157cb72c3e3
hex4af52b3fd

20121302013 has 4 divisors (see below), whose sum is σ = 26828402688. Its totient is φ = 13414201340.

The previous prime is 20121301997. The next prime is 20121302027. The reversal of 20121302013 is 31020312102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20121302013 - 24 = 20121301997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20121301983 and 20121302001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20121302413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3353550333 + ... + 3353550338.

It is an arithmetic number, because the mean of its divisors is an integer number (6707100672).

Almost surely, 220121302013 is an apocalyptic number.

It is an amenable number.

20121302013 is a deficient number, since it is larger than the sum of its proper divisors (6707100675).

20121302013 is an equidigital number, since it uses as much as digits as its factorization.

20121302013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6707100674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 20121302013 its reverse (31020312102), we get a palindrome (51141614115).

The spelling of 20121302013 in words is "twenty billion, one hundred twenty-one million, three hundred two thousand, thirteen".

Divisors: 1 3 6707100671 20121302013