2012140113 has 4 divisors (see below), whose sum is σ = 2682853488. Its totient is φ = 1341426740.

The previous prime is 2012140093. The next prime is 2012140129. The reversal of 2012140113 is 3110412102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2012140113 - 2¹² = 2012136017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2012140092 and 2012140101.

It is not an unprimeable number, because it can be changed into a prime (2012140153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335356683 + ... + 335356688.

It is an arithmetic number, because the mean of its divisors is an integer number (670713372).

Almost surely, 2^2012140113 is an apocalyptic number.

It is an amenable number.

2012140113 is a deficient number, since it is larger than the sum of its proper divisors (670713375).

2012140113 is an equidigital number, since it uses as much as digits as its factorization.

2012140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670713374.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 2012140113 is about 44856.8847892941. The cubic root of 2012140113 is about 1262.4651731464.

Adding to 2012140113 its reverse (3110412102), we get a palindrome (5122552215).

The spelling of 2012140113 in words is "two billion, twelve million, one hundred forty thousand, one hundred thirteen".