Base | Representation |
---|---|
bin | 1011111011000110111011… |
… | …1100000111011110100111 |
3 | 1201102022110111210012202021 |
4 | 2332301232330013132213 |
5 | 3204243441432043143 |
6 | 43514410352324011 |
7 | 2522113351403461 |
oct | 276615674073647 |
9 | 51368414705667 |
10 | 13110101440423 |
11 | 41a4a65535569 |
12 | 15789aa543607 |
13 | 74137b1b1630 |
14 | 334764893131 |
15 | 17b05561aced |
hex | bec6ef077a7 |
13110101440423 has 4 divisors (see below), whose sum is σ = 14118570782008. Its totient is φ = 12101632098840.
The previous prime is 13110101440417. The next prime is 13110101440433. The reversal of 13110101440423 is 32404410101131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13110101440423 - 241 = 10911078184871 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110101440433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504234670773 + ... + 504234670798.
It is an arithmetic number, because the mean of its divisors is an integer number (3529642695502).
Almost surely, 213110101440423 is an apocalyptic number.
13110101440423 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13110101440423 is a deficient number, since it is larger than the sum of its proper divisors (1008469341585).
13110101440423 is a wasteful number, since it uses less digits than its factorization.
13110101440423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1008469341584.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13110101440423 its reverse (32404410101131), we get a palindrome (45514511541554).
The spelling of 13110101440423 in words is "thirteen trillion, one hundred ten billion, one hundred one million, four hundred forty thousand, four hundred twenty-three".
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