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2012200122011 = 4373460141807
BaseRepresentation
bin11101010010000000011…
…110010011011010011011
321010100211200112021002212
4131102000132103122123
5230431441212401021
64140220355545335
7265243123554632
oct35220036233233
97110750467085
102012200122011
11706407569052
12285b898bb24b
13117998cc6891
146d568cc2519
153751e0cd85b
hex1d48079369b

2012200122011 has 4 divisors (see below), whose sum is σ = 2012660268192. Its totient is φ = 2011739975832.

The previous prime is 2012200121993. The next prime is 2012200122017. The reversal of 2012200122011 is 1102210022102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012200122011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012200122017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 230066531 + ... + 230075276.

It is an arithmetic number, because the mean of its divisors is an integer number (503165067048).

Almost surely, 22012200122011 is an apocalyptic number.

2012200122011 is a deficient number, since it is larger than the sum of its proper divisors (460146181).

2012200122011 is an equidigital number, since it uses as much as digits as its factorization.

2012200122011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 460146180.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 2012200122011 its reverse (1102210022102), we get a palindrome (3114410144113).

Subtracting from 2012200122011 its reverse (1102210022102), we obtain a palindrome (909990099909).

The spelling of 2012200122011 in words is "two trillion, twelve billion, two hundred million, one hundred twenty-two thousand, eleven".

Divisors: 1 4373 460141807 2012200122011