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20122013011 = 56935363819
BaseRepresentation
bin10010101111010111…
…011000110101010011
31220221100010011122011
4102233113120311103
5312202213404021
613124404323351
71311433200652
oct225727306523
956840104564
1020122013011
118596396221
123a969a3557
131b88a57b99
14d8c5a7199
157cb81cde1
hex4af5d8d53

20122013011 has 4 divisors (see below), whose sum is σ = 20157377400. Its totient is φ = 20086648624.

The previous prime is 20122012979. The next prime is 20122013017. The reversal of 20122013011 is 11031022102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20122013011 - 25 = 20122012979 is a prime.

It is a super-2 number, since 2×201220130112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20122012982 and 20122013000.

It is not an unprimeable number, because it can be changed into a prime (20122013017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17681341 + ... + 17682478.

It is an arithmetic number, because the mean of its divisors is an integer number (5039344350).

Almost surely, 220122013011 is an apocalyptic number.

20122013011 is a deficient number, since it is larger than the sum of its proper divisors (35364389).

20122013011 is an equidigital number, since it uses as much as digits as its factorization.

20122013011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35364388.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20122013011 its reverse (11031022102), we get a palindrome (31153035113).

Subtracting from 20122013011 its reverse (11031022102), we obtain a palindrome (9090990909).

The spelling of 20122013011 in words is "twenty billion, one hundred twenty-two million, thirteen thousand, eleven".

Divisors: 1 569 35363819 20122013011