Base | Representation |
---|---|
bin | 10010101111011011… |
… | …010100000011110011 |
3 | 1220221102001110012011 |
4 | 102233123110003303 |
5 | 312202444321120 |
6 | 13124442343351 |
7 | 1311445015015 |
oct | 225733240363 |
9 | 56842043164 |
10 | 20123042035 |
11 | 8596a29358 |
12 | 3a971bab57 |
13 | 1b89028385 |
14 | d8c7941b5 |
15 | 7cb972c5a |
hex | 4af6d40f3 |
20123042035 has 32 divisors (see below), whose sum is σ = 26014709952. Its totient is φ = 14887342080.
The previous prime is 20123042011. The next prime is 20123042041. The reversal of 20123042035 is 53024032102.
It is not a de Polignac number, because 20123042035 - 215 = 20123009267 is a prime.
It is a super-3 number, since 3×201230420353 (a number of 32 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20123041997 and 20123042015.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7688047 + ... + 7690663.
It is an arithmetic number, because the mean of its divisors is an integer number (812959686).
Almost surely, 220123042035 is an apocalyptic number.
20123042035 is a deficient number, since it is larger than the sum of its proper divisors (5891667917).
20123042035 is a wasteful number, since it uses less digits than its factorization.
20123042035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4183.
The product of its (nonzero) digits is 1440, while the sum is 22.
Adding to 20123042035 its reverse (53024032102), we get a palindrome (73147074137).
The spelling of 20123042035 in words is "twenty billion, one hundred twenty-three million, forty-two thousand, thirty-five".
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