Base | Representation |
---|---|
bin | 1001001001101010110101… |
… | …00011011110011111011101 |
3 | 2122020210010012112121110201 |
4 | 10210311122203132133131 |
5 | 10114200301400444013 |
6 | 110444325311503501 |
7 | 4144604425333006 |
oct | 444653243363735 |
9 | 78223105477421 |
10 | 20123441031133 |
11 | 6459337932840 |
12 | 2310083827b91 |
13 | b2c82b35bbab |
14 | 4d7da05b21ad |
15 | 24d6cbe9b3dd |
hex | 124d5a8de7dd |
20123441031133 has 4 divisors (see below), whose sum is σ = 21952844761248. Its totient is φ = 18294037301020.
The previous prime is 20123441031119. The next prime is 20123441031143. The reversal of 20123441031133 is 33113014432102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20123441031133 - 241 = 17924417775581 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20123441031143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 914701865041 + ... + 914701865062.
It is an arithmetic number, because the mean of its divisors is an integer number (5488211190312).
Almost surely, 220123441031133 is an apocalyptic number.
It is an amenable number.
20123441031133 is a deficient number, since it is larger than the sum of its proper divisors (1829403730115).
20123441031133 is a wasteful number, since it uses less digits than its factorization.
20123441031133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1829403730114.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 20123441031133 its reverse (33113014432102), we get a palindrome (53236455463235).
The spelling of 20123441031133 in words is "twenty trillion, one hundred twenty-three billion, four hundred forty-one million, thirty-one thousand, one hundred thirty-three".
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