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20124113413 = 157912744847
BaseRepresentation
bin10010101111011111…
…011001101000000101
31220221111001212211211
4102233133121220011
5312203233112123
613124521331421
71311460066405
oct225737315005
956844055754
1020124113413
1185975a0298
123a97636b71
131b89311c21
14d8c992805
157cbad540d
hex4af7d9a05

20124113413 has 4 divisors (see below), whose sum is σ = 20136859840. Its totient is φ = 20111366988.

The previous prime is 20124113411. The next prime is 20124113423. The reversal of 20124113413 is 31431142102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20124113413 - 21 = 20124113411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20124113411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6370845 + ... + 6374002.

It is an arithmetic number, because the mean of its divisors is an integer number (5034214960).

Almost surely, 220124113413 is an apocalyptic number.

It is an amenable number.

20124113413 is a deficient number, since it is larger than the sum of its proper divisors (12746427).

20124113413 is a wasteful number, since it uses less digits than its factorization.

20124113413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12746426.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 20124113413 its reverse (31431142102), we get a palindrome (51555255515).

The spelling of 20124113413 in words is "twenty billion, one hundred twenty-four million, one hundred thirteen thousand, four hundred thirteen".

Divisors: 1 1579 12744847 20124113413