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201241421303 = 1315480109331
BaseRepresentation
bin1011101101101011101…
…1000110010111110111
3201020102212020102101012
42323122323012113313
511244120300440203
6232240554022435
720352643600046
oct2733273062767
9636385212335
10201241421303
117838959941a
1233003417a1b
1315c915870b0
149a50d1455d
15537c442bd8
hex2edaec65f7

201241421303 has 4 divisors (see below), whose sum is σ = 216721530648. Its totient is φ = 185761311960.

The previous prime is 201241421287. The next prime is 201241421333. The reversal of 201241421303 is 303124142102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201241421303 - 24 = 201241421287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201241421333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7740054653 + ... + 7740054678.

It is an arithmetic number, because the mean of its divisors is an integer number (54180382662).

Almost surely, 2201241421303 is an apocalyptic number.

201241421303 is a deficient number, since it is larger than the sum of its proper divisors (15480109345).

201241421303 is a wasteful number, since it uses less digits than its factorization.

201241421303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15480109344.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 201241421303 its reverse (303124142102), we get a palindrome (504365563405).

The spelling of 201241421303 in words is "two hundred one billion, two hundred forty-one million, four hundred twenty-one thousand, three hundred three".

Divisors: 1 13 15480109331 201241421303