Base | Representation |
---|---|
bin | 101101110000011110100111… |
… | …010101101011000011010011 |
3 | 222101112200122112111202110212 |
4 | 231300132213111223003103 |
5 | 202334133142013134030 |
6 | 1552001553200514335 |
7 | 60250235352113513 |
oct | 5560364725530323 |
9 | 871480575452425 |
10 | 201243500130515 |
11 | 59138986464327 |
12 | 1a6a240901b9ab |
13 | 883a246b0cc8b |
14 | 379a34750d843 |
15 | 183ec12b97595 |
hex | b707a756b0d3 |
201243500130515 has 4 divisors (see below), whose sum is σ = 241492200156624. Its totient is φ = 160994800104408.
The previous prime is 201243500130493. The next prime is 201243500130521. The reversal of 201243500130515 is 515031005342102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 201243500130515 - 224 = 201243483353299 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20124350013047 + ... + 20124350013056.
It is an arithmetic number, because the mean of its divisors is an integer number (60373050039156).
Almost surely, 2201243500130515 is an apocalyptic number.
201243500130515 is a deficient number, since it is larger than the sum of its proper divisors (40248700026109).
201243500130515 is an equidigital number, since it uses as much as digits as its factorization.
201243500130515 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40248700026108.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 201243500130515 its reverse (515031005342102), we get a palindrome (716274505472617).
The spelling of 201243500130515 in words is "two hundred one trillion, two hundred forty-three billion, five hundred million, one hundred thirty thousand, five hundred fifteen".
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