Search a number
-
+
2012534555551 = 13154810350427
BaseRepresentation
bin11101010010010100011…
…010000100001110011111
321010101200222211020200021
4131102110122010032133
5230433132321234201
64140313504013011
7265254324316552
oct35222432041637
97111628736607
102012534555551
11706569320a03
12286061901167
13117a2038c650
146d59b49a699
153753d63eea1
hex1d49468439f

2012534555551 has 4 divisors (see below), whose sum is σ = 2167344905992. Its totient is φ = 1857724205112.

The previous prime is 2012534555527. The next prime is 2012534555573. The reversal of 2012534555551 is 1555554352102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2012534555551 - 235 = 1978174817183 is a prime.

It is a super-2 number, since 2×20125345555512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2012534555498 and 2012534555507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2012534555051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77405175201 + ... + 77405175226.

It is an arithmetic number, because the mean of its divisors is an integer number (541836226498).

Almost surely, 22012534555551 is an apocalyptic number.

2012534555551 is a deficient number, since it is larger than the sum of its proper divisors (154810350441).

2012534555551 is a wasteful number, since it uses less digits than its factorization.

2012534555551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154810350440.

The product of its (nonzero) digits is 750000, while the sum is 43.

The spelling of 2012534555551 in words is "two trillion, twelve billion, five hundred thirty-four million, five hundred fifty-five thousand, five hundred fifty-one".

Divisors: 1 13 154810350427 2012534555551