Base | Representation |
---|---|
bin | 1001001001110000010010… |
… | …10001110010000001000011 |
3 | 2122021001200111102211212212 |
4 | 10210320021101302001003 |
5 | 10114222302313432230 |
6 | 110445532225212335 |
7 | 4145040161524301 |
oct | 444701121620103 |
9 | 78231614384785 |
10 | 20126372405315 |
11 | 645a601590630 |
12 | 23107614910ab |
13 | b2cba7766227 |
14 | 4d819ba33271 |
15 | 24d7ee4d6895 |
hex | 124e09472043 |
20126372405315 has 32 divisors (see below), whose sum is σ = 26388145904832. Its totient is φ = 14614651648000.
The previous prime is 20126372405201. The next prime is 20126372405323. The reversal of 20126372405315 is 51350427362102.
It is not a de Polignac number, because 20126372405315 - 222 = 20126368211011 is a prime.
It is a super-3 number, since 3×201263724053153 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 182976935 + ... + 183086895.
It is an arithmetic number, because the mean of its divisors is an integer number (824629559526).
Almost surely, 220126372405315 is an apocalyptic number.
20126372405315 is a deficient number, since it is larger than the sum of its proper divisors (6261773499517).
20126372405315 is a wasteful number, since it uses less digits than its factorization.
20126372405315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115111.
The product of its (nonzero) digits is 302400, while the sum is 41.
Adding to 20126372405315 its reverse (51350427362102), we get a palindrome (71476799767417).
The spelling of 20126372405315 in words is "twenty trillion, one hundred twenty-six billion, three hundred seventy-two million, four hundred five thousand, three hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •