20130000113 has 4 divisors (see below), whose sum is σ = 20283664368. Its totient is φ = 19976335860.

The previous prime is 20130000103. The next prime is 20130000139. The reversal of 20130000113 is 31100003102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20130000113 - 2⁶ = 20130000049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20130000094 and 20130000103.

It is not an unprimeable number, because it can be changed into a prime (20130000103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76831931 + ... + 76832192.

It is an arithmetic number, because the mean of its divisors is an integer number (5070916092).

Almost surely, 2^20130000113 is an apocalyptic number.

It is an amenable number.

20130000113 is a deficient number, since it is larger than the sum of its proper divisors (153664255).

20130000113 is a wasteful number, since it uses less digits than its factorization.

20130000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 153664254.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 20130000113 its reverse (31100003102), we get a palindrome (51230003215).

The spelling of 20130000113 in words is "twenty billion, one hundred thirty million, one hundred thirteen", and thus it is an aban number.