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20130054401361 = 36839824331089
BaseRepresentation
bin1001001001110111001001…
…01111011110110101010001
32122021102012002202121220210
410210323210233132311101
510114302322411320421
6110451341435154333
74145230341134532
oct444734457366521
978242162677823
1020130054401361
116461120a13773
12231140a5a59a9
13b30343525108
144d842aa48689
1524d967893576
hex124ee4bded51

20130054401361 has 8 divisors (see below), whose sum is σ = 26879369862240. Its totient is φ = 13400387604032.

The previous prime is 20130054401339. The next prime is 20130054401423. The reversal of 20130054401361 is 16310445003102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20130054401361 - 217 = 20130054270289 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20130054401761) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4912163496 + ... + 4912167593.

It is an arithmetic number, because the mean of its divisors is an integer number (3359921232780).

Almost surely, 220130054401361 is an apocalyptic number.

It is an amenable number.

20130054401361 is a deficient number, since it is larger than the sum of its proper divisors (6749315460879).

20130054401361 is an equidigital number, since it uses as much as digits as its factorization.

20130054401361 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9824331775.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 20130054401361 its reverse (16310445003102), we get a palindrome (36440499404463).

The spelling of 20130054401361 in words is "twenty trillion, one hundred thirty billion, fifty-four million, four hundred one thousand, three hundred sixty-one".

Divisors: 1 3 683 2049 9824331089 29472993267 6710018133787 20130054401361