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201301024441 = 1118300093131
BaseRepresentation
bin1011101101111001111…
…0011101111010111001
3201020121000101120111211
42323132132131322321
511244231030240231
6232250523323121
720354266322116
oct2733636357271
9636530346454
10201301024441
117840a1a9110
123301b3804a1
1315ca0a2551a
149a58bcb90d
1553827b7eb1
hex2ede79deb9

201301024441 has 4 divisors (see below), whose sum is σ = 219601117584. Its totient is φ = 183000931300.

The previous prime is 201301024433. The next prime is 201301024549. The reversal of 201301024441 is 144420103102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 201301024441 - 23 = 201301024433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201301024411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9150046555 + ... + 9150046576.

It is an arithmetic number, because the mean of its divisors is an integer number (54900279396).

Almost surely, 2201301024441 is an apocalyptic number.

It is an amenable number.

201301024441 is a deficient number, since it is larger than the sum of its proper divisors (18300093143).

201301024441 is a wasteful number, since it uses less digits than its factorization.

201301024441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18300093142.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 201301024441 its reverse (144420103102), we get a palindrome (345721127543).

The spelling of 201301024441 in words is "two hundred one billion, three hundred one million, twenty-four thousand, four hundred forty-one".

Divisors: 1 11 18300093131 201301024441