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2013011311103 = 13154847023931
BaseRepresentation
bin11101010010110000110…
…100101111100111111111
321010102221012220221100022
4131102300310233213333
5230440121343423403
64140433054322355
7265302203552462
oct35226064574777
97112835827308
102013011311103
11706793451461
122861754b93bb
13117a98096620
146d6049212d9
153756a415d38
hex1d4b0d2f9ff

2013011311103 has 4 divisors (see below), whose sum is σ = 2167858335048. Its totient is φ = 1858164287160.

The previous prime is 2013011311097. The next prime is 2013011311121. The reversal of 2013011311103 is 3011131103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013011311103 - 26 = 2013011311039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013011317103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77423511953 + ... + 77423511978.

It is an arithmetic number, because the mean of its divisors is an integer number (541964583762).

Almost surely, 22013011311103 is an apocalyptic number.

2013011311103 is a deficient number, since it is larger than the sum of its proper divisors (154847023945).

2013011311103 is a wasteful number, since it uses less digits than its factorization.

2013011311103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154847023944.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 2013011311103 its reverse (3011131103102), we get a palindrome (5024142414205).

The spelling of 2013011311103 in words is "two trillion, thirteen billion, eleven million, three hundred eleven thousand, one hundred three".

Divisors: 1 13 154847023931 2013011311103