Base | Representation |
---|---|
bin | 11101010010110000110… |
… | …100101111100111111111 |
3 | 21010102221012220221100022 |
4 | 131102300310233213333 |
5 | 230440121343423403 |
6 | 4140433054322355 |
7 | 265302203552462 |
oct | 35226064574777 |
9 | 7112835827308 |
10 | 2013011311103 |
11 | 706793451461 |
12 | 2861754b93bb |
13 | 117a98096620 |
14 | 6d6049212d9 |
15 | 3756a415d38 |
hex | 1d4b0d2f9ff |
2013011311103 has 4 divisors (see below), whose sum is σ = 2167858335048. Its totient is φ = 1858164287160.
The previous prime is 2013011311097. The next prime is 2013011311121. The reversal of 2013011311103 is 3011131103102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2013011311103 - 26 = 2013011311039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013011317103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77423511953 + ... + 77423511978.
It is an arithmetic number, because the mean of its divisors is an integer number (541964583762).
Almost surely, 22013011311103 is an apocalyptic number.
2013011311103 is a deficient number, since it is larger than the sum of its proper divisors (154847023945).
2013011311103 is a wasteful number, since it uses less digits than its factorization.
2013011311103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154847023944.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 2013011311103 its reverse (3011131103102), we get a palindrome (5024142414205).
The spelling of 2013011311103 in words is "two trillion, thirteen billion, eleven million, three hundred eleven thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •