Base | Representation |
---|---|
bin | 101101110001010100011001… |
… | …000110110001010001010011 |
3 | 222101202012200202122211201112 |
4 | 231301110121012301101103 |
5 | 202341104421302320144 |
6 | 1552044303051323535 |
7 | 60254351316606656 |
oct | 5561243106612123 |
9 | 871665622584645 |
10 | 201301243401299 |
11 | 59160417a95318 |
12 | 1a6b16431505ab |
13 | 8842819b65522 |
14 | 379d06439989d |
15 | 184149222499e |
hex | b715191b1453 |
201301243401299 has 4 divisors (see below), whose sum is σ = 201301459845864. Its totient is φ = 201301026956736.
The previous prime is 201301243401283. The next prime is 201301243401317. The reversal of 201301243401299 is 992104342103102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 201301243401299 - 24 = 201301243401283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (201301243401239) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106821182 + ... + 108689315.
It is an arithmetic number, because the mean of its divisors is an integer number (50325364961466).
Almost surely, 2201301243401299 is an apocalyptic number.
201301243401299 is a deficient number, since it is larger than the sum of its proper divisors (216444565).
201301243401299 is an equidigital number, since it uses as much as digits as its factorization.
201301243401299 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 216444564.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 201301243401299 in words is "two hundred one trillion, three hundred one billion, two hundred forty-three million, four hundred one thousand, two hundred ninety-nine".
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