Search a number
-
+
201301243401300 = 2235277130734912601
BaseRepresentation
bin101101110001010100011001…
…000110110001010001010100
3222101202012200202122211201120
4231301110121012301101110
5202341104421302320200
61552044303051323540
760254351316606660
oct5561243106612124
9871665622584646
10201301243401300
1159160417a95319
121a6b16431505b0
138842819b65523
14379d0643998a0
1518414922249a0
hexb715191b1454

201301243401300 has 576 divisors, whose sum is σ = 679204328140800. Its totient is φ = 45082759680000.

The previous prime is 201301243401283. The next prime is 201301243401317. The reversal of 201301243401300 is 3104342103102.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (201301243401283) and next prime (201301243401317).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 15975015000 + ... + 15975027600.

It is an arithmetic number, because the mean of its divisors is an integer number (1179174180800).

Almost surely, 2201301243401300 is an apocalyptic number.

201301243401300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201301243401300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (339602164070400).

201301243401300 is an abundant number, since it is smaller than the sum of its proper divisors (477903084739500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201301243401300 is a wasteful number, since it uses less digits than its factorization.

201301243401300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13352 (or 13345 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 201301243401300 its reverse (3104342103102), we get a palindrome (204405585504402).

The spelling of 201301243401300 in words is "two hundred one trillion, three hundred one billion, two hundred forty-three million, four hundred one thousand, three hundred".