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2013013310311 = 16691206119419
BaseRepresentation
bin11101010010110000111…
…100010111101101100111
321010102221100200111202001
4131102300330113231213
5230440122401412221
64140433205230131
7265302226550203
oct35226074275547
97112840614661
102013013310311
117067945974a3
12286176102347
13117a986165a3
146d604cc1b03
153756a6ad391
hex1d4b0f17b67

2013013310311 has 4 divisors (see below), whose sum is σ = 2014219431400. Its totient is φ = 2011807189224.

The previous prime is 2013013310299. The next prime is 2013013310317. The reversal of 2013013310311 is 1130133103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013013310311 - 229 = 2012476439399 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013013310317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 603058041 + ... + 603061378.

It is an arithmetic number, because the mean of its divisors is an integer number (503554857850).

Almost surely, 22013013310311 is an apocalyptic number.

2013013310311 is a deficient number, since it is larger than the sum of its proper divisors (1206121089).

2013013310311 is a wasteful number, since it uses less digits than its factorization.

2013013310311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1206121088.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 2013013310311 its reverse (1130133103102), we get a palindrome (3143146413413).

The spelling of 2013013310311 in words is "two trillion, thirteen billion, thirteen million, three hundred ten thousand, three hundred eleven".

Divisors: 1 1669 1206119419 2013013310311