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20130140212023 = 313275056553683
BaseRepresentation
bin1001001001110111010011…
…10110110100101100110111
32122021102102002020021000110
410210323221312310230313
510114303011343241043
6110451354142314103
74145232432411432
oct444735166645467
978242362207013
1020130140212023
1164611653a3576
122311433288933
13b3035823b25a
144d84381c4819
1524d970193b33
hex124ee9db4b37

20130140212023 has 8 divisors (see below), whose sum is σ = 26860413169408. Its totient is φ = 13409980364664.

The previous prime is 20130140212009. The next prime is 20130140212079. The reversal of 20130140212023 is 32021204103102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20130140212023 - 26 = 20130140211959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130140212003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2528272861 + ... + 2528280822.

It is an arithmetic number, because the mean of its divisors is an integer number (3357551646176).

Almost surely, 220130140212023 is an apocalyptic number.

20130140212023 is a deficient number, since it is larger than the sum of its proper divisors (6730272957385).

20130140212023 is a wasteful number, since it uses less digits than its factorization.

20130140212023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5056555013.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 20130140212023 its reverse (32021204103102), we get a palindrome (52151344315125).

The spelling of 20130140212023 in words is "twenty trillion, one hundred thirty billion, one hundred forty million, two hundred twelve thousand, twenty-three".

Divisors: 1 3 1327 3981 5056553683 15169661049 6710046737341 20130140212023