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20130144414203 = 53379814045551
BaseRepresentation
bin1001001001110111010100…
…00110110110100111111011
32122021102102101010202022202
410210323222012312213323
510114303013432223303
6110451354412340415
74145232513212615
oct444735206664773
978242371122282
1020130144414203
11646116780374a
12231143477470b
13b3035907cb55
144d8438999db5
1524d970723c88
hex124eea1b69fb

20130144414203 has 4 divisors (see below), whose sum is σ = 20509958459808. Its totient is φ = 19750330368600.

The previous prime is 20130144414181. The next prime is 20130144414239. The reversal of 20130144414203 is 30241444103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20130144414203 - 214 = 20130144397819 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20130144414253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189907022723 + ... + 189907022828.

It is an arithmetic number, because the mean of its divisors is an integer number (5127489614952).

Almost surely, 220130144414203 is an apocalyptic number.

20130144414203 is a deficient number, since it is larger than the sum of its proper divisors (379814045605).

20130144414203 is an equidigital number, since it uses as much as digits as its factorization.

20130144414203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 379814045604.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 20130144414203 its reverse (30241444103102), we get a palindrome (50371588517305).

The spelling of 20130144414203 in words is "twenty trillion, one hundred thirty billion, one hundred forty-four million, four hundred fourteen thousand, two hundred three".

Divisors: 1 53 379814045551 20130144414203