Base | Representation |
---|---|
bin | 11101010010110001000… |
… | …000101100000110101011 |
3 | 21010102221102211000200200 |
4 | 131102301000230012223 |
5 | 230440123144124121 |
6 | 4140433245403243 |
7 | 265302242303610 |
oct | 35226100540653 |
9 | 7112842730620 |
10 | 2013014442411 |
11 | 7067951a0015 |
12 | 286176569523 |
13 | 117a9892197b |
14 | 6d6050d8507 |
15 | 3756a833a26 |
hex | 1d4b102c1ab |
2013014442411 has 48 divisors (see below), whose sum is σ = 3370405910976. Its totient is φ = 1133925931008.
The previous prime is 2013014442337. The next prime is 2013014442497. The reversal of 2013014442411 is 1142444103102.
2013014442411 is a `hidden beast` number, since 201 + 3 + 0 + 1 + 4 + 4 + 42 + 411 = 666.
It is not a de Polignac number, because 2013014442411 - 222 = 2013010248107 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2013014442211) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8497081 + ... + 8730773.
It is an arithmetic number, because the mean of its divisors is an integer number (70216789812).
Almost surely, 22013014442411 is an apocalyptic number.
2013014442411 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2013014442411 is a deficient number, since it is larger than the sum of its proper divisors (1357391468565).
2013014442411 is a wasteful number, since it uses less digits than its factorization.
2013014442411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235652 (or 235649 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 2013014442411 its reverse (1142444103102), we get a palindrome (3155458545513).
The spelling of 2013014442411 in words is "two trillion, thirteen billion, fourteen million, four hundred forty-two thousand, four hundred eleven".
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