201302001112021 has 4 divisors (see below), whose sum is σ = 203295090232044. Its totient is φ = 199308911992000.

The previous prime is 201302001111997. The next prime is 201302001112081. The reversal of 201302001112021 is 120211100203102.

201302001112021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 194615194707025 + 6686806404996 = 13950455^2 + 2585886^2 .

It is a cyclic number.

It is not a de Polignac number, because 201302001112021 - 2²¹ = 201301999014869 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201302001111986 and 201302001112004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201302001112081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 996544559860 + ... + 996544560061.

It is an arithmetic number, because the mean of its divisors is an integer number (50823772558011).

Almost surely, 2^{201302001112021} is an apocalyptic number.

It is an amenable number.

201302001112021 is a deficient number, since it is larger than the sum of its proper divisors (1993089120023).

201302001112021 is a wasteful number, since it uses less digits than its factorization.

201302001112021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1993089120022.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 201302001112021 its reverse (120211100203102), we get a palindrome (321513101315123).

The spelling of 201302001112021 in words is "two hundred one trillion, three hundred two billion, one million, one hundred twelve thousand, twenty-one".