20130202111333 has 4 divisors (see below), whose sum is σ = 20130238773568. Its totient is φ = 20130165449100.

The previous prime is 20130202111211. The next prime is 20130202111363. The reversal of 20130202111333 is 33311120203102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20130202111333 - 2¹⁷ = 20130201980261 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130202111363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17494791 + ... + 18609892.

It is an arithmetic number, because the mean of its divisors is an integer number (5032559693392).

Almost surely, 2^{20130202111333} is an apocalyptic number.

It is an amenable number.

20130202111333 is a deficient number, since it is larger than the sum of its proper divisors (36662235).

20130202111333 is an equidigital number, since it uses as much as digits as its factorization.

20130202111333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36662234.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 20130202111333 its reverse (33311120203102), we get a palindrome (53441322314435).

The spelling of 20130202111333 in words is "twenty trillion, one hundred thirty billion, two hundred two million, one hundred eleven thousand, three hundred thirty-three".