Base | Representation |
---|---|
bin | 11101010010110001011… |
… | …001110010101110011011 |
3 | 21010102221220012100202001 |
4 | 131102301121302232123 |
5 | 230440131340220011 |
6 | 4140434042421431 |
7 | 265302352242436 |
oct | 35226131625633 |
9 | 7112856170661 |
10 | 2013021023131 |
11 | 706798985228 |
12 | 286178801877 |
13 | 117a9a0b70a1 |
14 | 6d605d2c81d |
15 | 3756b1d37c1 |
hex | 1d4b1672b9b |
2013021023131 has 4 divisors (see below), whose sum is σ = 2082435541200. Its totient is φ = 1943606505064.
The previous prime is 2013021023113. The next prime is 2013021023149. The reversal of 2013021023131 is 1313201203102.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (2013021023113) and next prime (2013021023149).
It is a cyclic number.
It is not a de Polignac number, because 2013021023131 - 221 = 2013018925979 is a prime.
It is a super-2 number, since 2×20130210231312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2013021023099 and 2013021023108.
It is not an unprimeable number, because it can be changed into a prime (2013021023161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34707258991 + ... + 34707259048.
It is an arithmetic number, because the mean of its divisors is an integer number (520608885300).
Almost surely, 22013021023131 is an apocalyptic number.
2013021023131 is a deficient number, since it is larger than the sum of its proper divisors (69414518069).
2013021023131 is an equidigital number, since it uses as much as digits as its factorization.
2013021023131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69414518068.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2013021023131 its reverse (1313201203102), we get a palindrome (3326222226233).
The spelling of 2013021023131 in words is "two trillion, thirteen billion, twenty-one million, twenty-three thousand, one hundred thirty-one".
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